|
A
B K = 2 versus B
A K = ½ |
Up until now we have been dealing with the following equilibrium:
N2 + 3H2 
2NH3 Kc = 0.25 (The magnitude of K depends on temperature.)
Let's form an equilibrium with this reaction just like you have done already.
Go ahead and put 3 moles of N2, H2,
and NH3 into the reaction vessel and press "equilibrate".
Write down the number of moles of each substance that you have at equilibrium.
Now let's say that we have the reverse of the equilbrium that we have
been using. That is, let's say that we have the following equilibrium:
2NH3
N2 + 3H2 Kc =__?__.
Calculate the value of "Kc". Assume that the temperature has not changed.
If you place 3 moles of NH3, N2,
and H2 into a reaction vessel,
and the equilibrium is 2NH3
N2 + 3H2, how many moles of
each species will you have at equilibrium?
